Can you solve the sea monster riddle Dan Finkel

According to legend,
once every thousand years

a host of sea monsters emerges
from the depths to demand tribute

from the floating city of Atlantartica.

As the ruler of the city,
you’d always dismissed the stories…

until today, when 7 Leviathan Lords
rose out of the roiling waters

and surrounded your city.

Each commands 10 giant kraken,

and each kraken
is accompanied by 12 mermites.

Your city’s puny army
is hopelessly outmatched.

You think back to the legends.

In the stories, the ruler of the city
saved his people

by feeding the creatures
a ransom of pearls.

The pearls would be split equally
between the leviathans lords.

Each leviathan would then divide its share
into 11 equal piles, keeping one,

and giving the other 10
to their kraken commanders.

Each kraken would then divide its share
into 13 equal piles,

keeping one, and distributing the other
twelve to their mermite minions.

If any one of these divisions left
an unequal pile or leftover pearl,

the monsters would pull everyone
to the bottom of the sea.

Such was the fate
of your fabled sister city.

You rush to the ancient treasure room
and find five chests,

each containing a precisely counted number
of pearls

prepared by your ancestors
for exactly this purpose.

Each of the chests bears a number
telling how many pearls it contains.

Unfortunately, the symbols they used
to write digits 1,000 years ago

have changed with time,

and you don’t know how
to read the ancient numbers.

With hundreds of thousands of pearls
in each chest, there’s no time to recount.

One of these chests will save your city

and the rest will lead
to its certain doom.

Which do you choose?

Pause the video to figure it out yourself.

Answer in 3

Answer in 2

Answer in 1

There isn’t enough information to decode
the ancient Atlantartican numeral system.

But all hope is not lost,

because there’s another piece
of information those symbols contain:

patterns.

If we can find a matching pattern
in arabic numerals,

we can still pick the right chest.

Let’s take stock of what we know.

A quantity of pearls that can appease
the sea monsters

must be divisible by 7, 11, and 13.

Rather than trying out numbers
at random,

let’s examine ones that have this property

and see if there are any
patterns that unite them.

Being divisible by 7, 11, and 13

means that our number must
be a multiple of 7, 11, and 13.

Those three numbers are all prime,
so multiplying them together

will give us their least
common multiple: 1001.

That’s a useful starting place

because we now know that any viable
offering to the sea monsters

must be a multiple of 1001.

Let’s try multiplying it by a three digit
number,

just to get a feel for what we might get.

If we try 861 times 1001, we get 861,861,

and we see something similar
with other examples.

It’s a peculiar pattern.

Why would multiplying a three-digit
number by 1001

end up giving you two copies
of that number,

written one after the other?

Breaking down the multiplication
problem can give us the answer.

1001 times any number x is equal
to 1000x + x.

For example, 725 times 1000 is 725,000,
and 725 x 1 is 725.

So 725 x 1001 will be the sum of
those two numbers: 725,725.

And there’s nothing special about 725.

Pick any three-digit number,

and your final product will have
that many thousands, plus one more.

Even though you don’t know how
to read the numbers on the chests,

you can read which pattern of digits
represents a number divisible by 1001.

As with many problems, trying concrete
examples can give you an intuition

for behavior that may at first look
abstract and mysterious.

The monsters accept your ransom
and swim back down to the depths

for another thousand years.

With the proper planning,

that should give you plenty of time
to prepare for their inevitable return.

相传,
每隔一千年,就会

有一大群海怪从海底出现

向漂浮的亚特兰大城市亚特兰大求贡。

作为城市的统治者,
你总是对这些故事不屑一顾……

直到今天,七位利维坦领主
从汹涌的水中升起

并包围了你的城市。

每个命令 10 个巨型海妖

,每个海妖
都伴随着 12 个默米特人。

你所在城市的微弱军队
已经无可匹敌了。

你回想传说。

在故事中,城市的统治者


珍珠作为赎金来拯救他的人民。

珍珠将
在利维坦领主之间平分。

然后,每只巨兽将其份额
分成 11 等份,保留一份

,将另外 10 份
交给他们的海妖指挥官。

然后,每只海妖将其份额
分成 13 等份,

保留一份,将另外
12 份分配给它们的鱼尾怪爪牙。

如果这些师中的任何一个留下
了不等的一堆或剩下的珍珠

,怪物就会把所有人都
拉到海底。

这就是
你传说中的姐妹城市的命运。

你冲到古老的宝藏室
,发现五个箱子,每个箱子里

都装着精确计算数量
的珍珠,这些珍珠

是你的祖先
专门为此准备的。

每个箱子上都有一个数字,
说明里面有多少珍珠。

不幸的是,
1000年前他们用来书写数字的符号

随着时间的推移而变化,

你不知道
如何阅读古代数字。

每个箱子里都有几十万颗珍珠
,来不及细数。

其中一个箱子将拯救你的城市

,其余的将
导致其注定的厄运。

你选择哪个?

暂停视频以自己弄清楚。

回答 3

回答 2

回答 1

没有足够的信息来
解码古老的亚特兰大数字系统。

但是所有的希望都没有丢失,

因为
这些符号包含另一条信息:

模式。

如果我们能在阿拉伯数字中找到匹配的图案

我们仍然可以选择正确的箱子。

让我们盘点一下我们所知道的。

能够安抚海怪的珍珠数量

必须能被 7、11 和 13 整除。

与其随机尝试数字,不如

让我们检查具有此属性的珍珠

,看看是否有任何
模式可以将它们结合在一起。

能被 7、11 和 13 整除

意味着我们的数字必须
是 7、11 和 13 的倍数。

这三个数字都是素数,
因此将它们相乘

将得到它们的
最小公倍数:1001。

这是一个有用的开始

因为我们现在知道任何可行
的海怪祭品都

必须是 1001 的倍数。

让我们尝试将它乘以一个
三位数,

只是为了感受一下我们可能会得到什么。

如果我们尝试 861 次 1001,我们得到 861,861

,我们看到
与其他示例类似的情况。

这是一种奇特的模式。

为什么将一个三位
数字乘以 1001

最终会得到
该数字的两个副本,

一个接一个地写出来?

分解乘法
问题可以给我们答案。

任何数 x 的 1001 次
等于 1000x + x。

例如,725 乘以 1000 是 725,000,725
x 1 是 725。

所以 725 x 1001 将是
这两个数字的总和:725,725。

725 并没有什么特别之处。

选择任何三位数

,您的最终产品将
有数千个,再加上一个。

即使您不知道
如何阅读箱子上的数字,

您也可以阅读哪种数字模式
代表一个可被 1001 整除的数字。

与许多问题一样,尝试具体
示例可以让您对乍一看的行为有直觉

抽象而神秘。

怪物们接受了你的赎金
并再次游回

深处一千年。

通过适当的计划,

您应该有足够的时间
为他们不可避免的回归做准备。