The math behind Michael Jordans legendary hang time Andy Peterson and Zack Patterson

Michael Jordan once said,

“I don’t know whether I’ll fly or not.

I know that when I’m in the air

sometimes I feel like I don’t ever
have to come down.”

But thanks to Isaac Newton,

we know that what goes up
must eventually come down.

In fact, the human limit
on a flat surface for hang time,

or the time from when your feet leave
the ground to when they touch down again,

is only about one second,

and, yes, that even includes his airness,

whose infamous dunk
from the free throw line

has been calculated at .92 seconds.

And, of course, gravity is what’s making it
so hard to stay in the air longer.

Earth’s gravity pulls all nearby objects
towards the planet’s surface,

accelerating them
at 9.8 meters per second squared.

As soon as you jump,
gravity is already pulling you back down.

Using what we know about gravity,

we can derive a fairly simple equation
that models hang time.

This equation states that the height
of a falling object above a surface

is equal to the object’s initial height
from the surface plus its initial velocity

multiplied by how many seconds
it’s been in the air,

plus half of the
gravitational acceleration

multiplied by the square of the number
of seconds spent in the air.

Now we can use this equation to model
MJ’s free throw dunk.

Say MJ starts, as one does,
at zero meters off the ground,

and jumps with an initial vertical
velocity of 4.51 meters per second.

Let’s see what happens if we model
this equation on a coordinate grid.

Since the formula is quadratic,

the relationship between height
and time spent in the air

has the shape of a parabola.

So what does it tell us about MJ’s dunk?

Well, the parabola’s vertex shows us
his maximum height off the ground

at 1.038 meters,

and the X-intercepts tell us
when he took off

and when he landed,
with the difference being the hang time.

It looks like Earth’s gravity
makes it pretty hard

for even MJ to get some solid hang time.

But what if he were playing an away game
somewhere else, somewhere far?

Well, the gravitational acceleration
on our nearest planetary neighbor, Venus,

is 8.87 meters per second squared,
pretty similar to Earth’s.

If Michael jumped here with the same
force as he did back on Earth,

he would be able to get more
than a meter off the ground,

giving him a hang time
of a little over one second.

The competition on Jupiter
with its gravitational pull

of 24.92 meters per second squared
would be much less entertaining.

Here, Michael wouldn’t even
get a half meter off the ground,

and would remain airborne
a mere .41 seconds.

But a game on the moon
would be quite spectacular.

MJ could take off from behind half court,

jumping over six meters high,

and his hang time of over
five and half seconds,

would be long enough for anyone
to believe he could fly.

迈克尔乔丹曾经说过,

“我不知道我是否会飞。

我知道当我在空中时,

有时我觉得我永远
不必下来。”

但是多亏了艾萨克·牛顿,

我们知道上升的东西
最终一定会下降。

事实上,人类
在平面上停留时间的限制,

或者说从你的脚
离开地面到再次触地的时间

,只有大约一秒,

而且,是的,这甚至包括他那

臭名昭著的扣篮
距离罚球线的距离

计算为 0.92 秒。

而且,当然,重力是
让在空中停留更长时间变得如此困难的原因。

地球的引力将所有附近的物体拉
向地球表面,

以每秒 9.8 米的速度加速它们。

一旦你跳起来,
重力就已经把你拉下来了。

利用我们对重力的了解,

我们可以推导出一个相当简单的方程
来模拟悬挂时间。

这个方程表明,
下落物体在表面上方的高度

等于物体距表面的初始高度
加上它的初始速度

乘以
它在空中的秒数,

再加上一半的
重力加速度

乘以平方
在空中停留的秒数。

现在我们可以使用这个方程来模拟
MJ 的罚球扣篮。

假设 MJ
在离地 0 米处开始,

并以
每秒 4.51 米的初始垂直速度跳跃。

让我们看看如果我们
在坐标网格上建模这个方程会发生什么。

由于公式是二次的,

因此高度
和在空中

停留的时间之间的关系具有抛物线的形状。

那么关于 MJ 的扣篮,它告诉了我们什么?

好吧,抛物线的顶点向我们展示了
他离地的最大高度

为 1.038 米,

而 X 截距告诉我们
他何时起飞

和何时着陆
,不同之处在于悬挂时间。

看起来地球的引力
使得

即使是 MJ 也很难获得一些稳定的悬挂时间。

但是,如果他在其他地方打客场比赛
,在遥远的地方怎么办?

好吧,
我们最近的行星邻居金星的重力加速度

是每秒 8.87 米,
与地球的非常相似。

如果迈克尔
以他在地球上的相同力量跳到这里,

他将能够
离开地面超过一米,

给他
一秒多一点的悬挂时间。

木星上的比赛
,其引力

为每秒 24.92 米,
娱乐性要低得多。

在这里,迈克尔甚至
不会离开地面半米,

并且只会在
空中停留 0.41 秒。

但是在月球上进行一场比赛
会非常壮观。

MJ 可以从半场后起跳,

跳跃超过 6 米高

,他的悬停时间超过
5 秒半,

足以让任何
人相信他会飞。