Can you solve the riddle and escape Hades Dan Finkel

Maybe the fates got clumsy.

Maybe Poseidon had one of his angry days.

However it happened,
the underworld is overcrowded,

and Zeus has ordered Hades
to let some spirits out.

Hades arranges all the souls
of the dead in a line before Cerberus.

When one of his three heads bites
down on the soul in front of it,

they’ll get returned
to the land of the living.

Anyone to the left must get out
of line and stay in Hades forever.

And everyone else shuffles forward,
at which point Cerberus will feed again.

Each of the dog’s heads has an equal
chance of being the one to bite each time,

and no two ever bite simultaneously.

Unfortunately, Hades’ minions forgot
to tell you what was happening,

and by the time you show up
there are only 99 souls left in line.

Hades looks furious and drawing attention
to yourself won’t end well.

But suddenly, time freezes,
and Hermes steps out of the shadows.

He tells you he can instantly put
you into the line,

and no one will realize what happened.

But he’ll only grant his grace
to someone clever enough

to take full advantage of it.

Choose the best place in line
and he’ll give you the spot.

Choose wrong, and he’ll leave you to rot.

Which spot should you pick?

Pause the video to figure it out yourself.

Answer in 3

Answer in 2

Answer in 1

It’s possible to calculate the exact
probability of going free

in all 100 spots.

But there’s a much simpler path
to the solution

that requires surprisingly
little calculation.

Imagine being anywhere in line.

Way up at the front, one of the three
heads will pick someone at random,

and you’ll move forward 1, 2, or 3 spaces.

Since each is equally likely,

your chance of survival
from wherever you started

is the average of the chances from
each of the three spaces in front of you.

And this is where you can
find a huge shortcut.

Averages must be on or between
the extremes of what you’re averaging—

they can never be higher
than the highest value

or lower than the lowest.

So whatever your chances of survival
are where you start,

one of the three places in front
of you is at least as good,

and probably better.

This observation is incredibly powerful.

It means that wherever you are in line,

it’d be wise to trade your place for one
of the three spots in front of you.

Let’s ignore which for now and think
of them as a trio—

this trio’s maximum value
is better than this trio’s, and so on.

Keep going and you’ll reach the front…

These three spots must contain
the extreme values—

the best and worst probabilities—

for the entire line.

In other words,
they’re all we need to consider.

Place 1 is bad.

Head one would save you, and the other
two doom you forever.

That’s just a 1 in 3 chance to escape.

Place 2 is better: head two is great,

head 3 is bad, and head 1 is ok
in that it gives you another chance.

But place 3 is best,
because head 3 saves you

while heads 1 and 2 both
give you extra chances.

If you did want to consider
the exact probabilities,

the odds of surviving in place 3
are 16 out of 27, or close to 60%.

The spots later in line tend to be very
close to having a 50% chance of survival.

Why 50%?

Because every time Cerberus sends
one soul up to be reborn,

he leaves 0, 1, or 2 souls
in the underworld.

That averages out to one person
staying for each one who gets freed.

But you can beat those odds handily
with what you now know.

Hermes has places to be, and so do you.

He rewards your insight by sneaking
you into the third spot.

And from there it’ll be just a short wait
to learn your ultimate fate.

也许命运变得笨拙。

也许波塞冬有他愤怒的日子之一。

无论如何
,冥界人满为患

,宙斯命令
哈迪斯放出一些灵魂。

哈迪斯将所有
死者的灵魂排成一列,出现在刻耳柏洛斯面前。

当他的三个头颅中的一个
咬住它面前的灵魂时,

它们就会回到
生者的土地上。

左边的任何人都必须
脱离常规,永远留在哈迪斯。

其他所有人都向前移动,
此时 Cerberus 将再次进食。

每只狗的头
每次被咬的机会都是相同的,

而且没有两个人会同时咬人。

不幸的是,哈迪斯的爪牙忘
了告诉你发生了什么

,当你出现时,排队的
人只剩下 99 个。

哈迪斯看起来很生气,引起
对自己的关注不会有好结果。

但突然,时间凝固了
,赫尔墨斯走出了阴影。

他告诉你他可以立即让
你加入队伍

,没有人会意识到发生了什么。

但他只会把他的恩典
赐给足够聪明、

能够充分利用它的人。

选择排队的最佳位置
,他会给你位置。

选错了,他会让你腐烂。

你应该选择哪个位置?

暂停视频以自己弄清楚。

回答 3

回答 2

回答

1 可以计算出

在所有 100 个点中自由的确切概率。

但是有一个更
简单的解决

方案,只需要
很少的计算。

想象一下在任何地方排队。

在前面,三个
头中的一个会随机选择一个人

,您将向前移动 1、2 或 3 个空格。

由于每一个都有同样的可能性,所以


从你开始的地方生存

的机会
是你面前三个空间中每一个空间的机会的平均值。

在这里你可以
找到一条巨大的捷径。

平均值必须在你所平均的极端值之上或之间——

它们永远不能
高于最高值

或低于最低值。

所以无论你的生存机会
是从哪里开始的,

你面前的三个地方之一
至少一样好,

而且可能更好。

这个观察力非常强大。

这意味着无论您在哪里排队,

明智的做法是将您的位置
换成您面前的三个位置之一。

让我们暂时忽略哪个,
将它们视为一个

三重奏——这个三重奏的
最大值比这个三重奏的要好,以此类推。

继续前进,您将到达前线……

这三个点必须包含整个线路
的极值——

最佳和最差

概率。

换句话说,
它们是我们需要考虑的全部。

地方 1 很糟糕。

第一个会拯救你,而另外
两个会永远毁灭你。

这只是三分之一的逃脱机会。

地方 2 更好: 头部 2 很棒,

头部 3 不好,头部 1 还可以
,因为它给了你另一个机会。

但是位置 3 是最好的,
因为头 3 可以拯救你,

而头 1 和 2
都给你额外的机会。

如果您确实想
考虑确切的概率,

那么在第 3 位生存的几率
是 27 人中的 16 人,或接近 60%。

排在后面的位置往往非常
接近 50% 的生存机会。

为什么是 50%?

因为每次 Cerberus 将
一个灵魂送上去重生,

他都会在冥界留下 0、1 或 2 个灵魂

平均而言
,每个获释的人留下一个人。

但是你可以
用你现在所知道的轻松战胜这些可能性。

爱马仕有地方可去,你也一样。

他通过偷偷带
你进入第三个位置来奖励你的洞察力。

从那里开始,您只需稍等片刻
即可了解您的最终命运。