Can you solve the wizard standoff riddle Dan Finkel

You’ve been chosen as a champion
to represent your wizarding house

in a deadly duel against
two rival magic schools.

Your opponents are fearsome.

From the Newt-niz school,

a powerful sorcerer wields a wand
that can turn people into fish,

but his spell only works 70% of the time.

And from the Leib-ton school,

an even more powerful enchantress wields
a wand that turns people to statues,

and it works 90% of the time.

Lots are drawn, and you’re chosen
to cast the first spell in the duel.

The Newt-niz magician will go second,

and the Leib-ton enchantress third,

after which you’ll repeat casting in
that order until only one of you is left.

The rules of magic duels are strict,

and anyone who casts out of
order immediately forfeits the duel.

Also, to prevent draws,

the rules stipulate that
if everyone’s still standing

at the end of the first round,

you’ll all be turned into cats.

Now, you must choose a wand.

Your wizarding house presents you
with three options:

the Bannekar, which binds
one target with vines

and casts effectively 60% of the time,

the Gaussian,
which turns one target into a tree

and works 80% of the time,

and the incredibly rare Noether 9000,

which banishes one target
to a distant mountaintop

and casts perfectly 100% of the time.

Your opponents are masters of strategy,
as well as sorcery,

and you know they’ll make the choices that
maximize their own chances of success.

Which wand should you choose

and what strategy should you employ

to have the greatest chance
of winning the duel?

Pause the video now if you want
to figure it out for yourself!

Answer in: 3

Answer in: 2

Answer in: 1

You reach for the Noether 9000 first.

After all, it makes sense to enter
the duel with the most powerful wand.

But before you pick it up, you consider
what would happen.

As the most dangerous wizard,

you’d also be the target
of the other two magicians,

and you’d need to take
care of the most dangerous of them first.

But afterward, there’s a 70% chance you’d
be struck down by the remaining wizard.

That’s trouble.

Maybe it’s better to take the Gaussian.

It works 80% of the time,

which means you wouldn’t be a target
until the enchantress was incapacitated.

But if you succeeded in transforming her,

you’d probably be turned
into a fish immediately after.

If you transformed the sorcerer,

the enchantress would almost
certainly turn you to stone.

It would really be better if you missed.

And that’s when you have an idea:

what if you took the Gaussian,
then missed on purpose?

Then, you would wait for the sorcerer
to attack the enchantress,

and you’d have an 80% chance
of winning against the sorcerer.

It’s a good idea, but there’s a problem;

the sorcerer could also pass his turn

and the enchantress, knowing that
she couldn’t pass without becoming a cat,

would cast her spell on one of you.

And since you’re the most dangerous
between you and the sorcerer,

you’d be the target.

And that’s when you see
what you really need to do:

take the weakest wand, the Bannekar,
and miss on purpose.

Now the sorcerer knows that
he’ll be targeted by the enchantress

and he’ll have to try to turn her into
a fish to avoid being turned into stone.

Seventy percent of the time he’d succeed

and you’d have a 60% chance
of winning the duel

at the beginning of the next round.

If he fails, chances are he’ll be
turned to stone

and you’d still have a 60% chance of
winning the duel against the enchantress.

There’s a slim 3% chance
you’ll all be turned into cats,

but when everything’s accounted for,

you have better than even odds
of winning with this strategy.

And that’s the best you can do.

Here’s what the probability of winning
for the different strategies looks like.

Who would’ve thought
that the best way to take your shot

would be to throw away your shot?

你被选为冠军
,代表你的巫师

学院与两个敌对的魔法学校进行一场致命的决斗。

你的对手很可怕。

来自 Newt-niz 学校的

一位强大的巫师挥舞着一根
可以把人变成鱼的魔杖,

但他的咒语只有 70% 的时间有效。

而在莱布顿学校,

一个更强大的女巫挥舞着
一根魔杖,可以把人变成雕像,

而且 90% 的时间都有效。

抽签,你被选中
施展决斗中的第一个咒语。

Newt-niz 魔术师将排在第二位

,Leib-ton 女巫排在第三位,

之后您将
按此顺序重复施法,直到只剩下一个人。

魔法决斗的规则是严格的

,任何施法失常的人都会
立即失去决斗的资格。

另外,为了防止平局

,规则规定
如果第一轮结束时每个人都还站着

那么你们都会变成猫。

现在,你必须选择一根魔杖。

你的巫师屋为你
提供了三种选择

:Bannekar,
用藤蔓束缚一个目标

并在 60% 的时间内有效施法

,Gaussian
,将一个目标变成一棵树

并在 80% 的时间内有效,

以及极其罕见的 Noether 9000,

将一个目标放逐
到遥远的山顶,

并在 100% 的时间内完美地施放。

您的对手既精通战略,
又精通巫术

,您知道他们会做出
最大程度地提高自己成功机会的选择。

你应该选择哪根魔杖,

你应该采用什么策略

来赢得决斗的最大
机会?

如果您
想自己解决问题,请立即暂停视频!

答案:3

答案:2

答案:1

您首先到达 Noether 9000。

毕竟,
用最强大的魔杖进入决斗是有道理的。

但在你拿起它之前,你会考虑
会发生什么。

作为最危险的巫师,

你也将
成为另外两个魔法师的目标

,你需要先解决
他们中最危险的一个。

但之后,你有 70% 的机会会
被剩下的巫师击倒。

这很麻烦。

也许最好采用高斯。

它在 80% 的时间里都有效,

这意味着
在女巫失去能力之前你不会成为目标。

但如果你改造成功了,

你可能
马上就会变成一条鱼。

如果你改造了巫师

,女巫几乎
肯定会把你变成石头。

如果你错过了,那真的会更好。

这时候你就有了一个想法

:如果你拿了高斯,
然后故意错过了怎么办?

然后,等待
巫师攻击女巫

,你将有 80% 的
机会战胜巫师。

这是个好主意,但有一个问题;

巫师也可以通过他的回合

,而女巫知道如果
不变成猫就无法通过,

她会对你们中的一个人施法。

既然你是
你和巫师之间最危险的人,

你就会成为目标。


就是你真正需要做的事情的时候:

拿起最弱的魔杖,Bannekar,
然后故意错过。

现在巫师知道
他会成为女巫的目标

,他必须尝试将她变成
一条鱼,以免变成石头。

70% 的机会他会成功,

而你有 60% 的机会

在下一轮开始时赢得决斗。

如果他失败了,他很可能会
变成石头,

而你仍然有 60% 的机会
赢得与女巫的决斗。

你们全都变成猫的几率只有 3

%,但如果考虑到所有因素,

使用这种策略获胜的几率甚至更高。

这是你能做的最好的。

以下是
不同策略获胜的概率。

谁会
想到最好的

投篮方式就是扔掉你的投篮?