What is Zenos Dichotomy Paradox Colm Kelleher

Translator: Andrea McDonough
Reviewer: Bedirhan Cinar

This is Zeno of Elea,

an ancient Greek philosopher

famous for inventing a number of paradoxes,

arguments that seem logical,

but whose conclusion is absurd or contradictory.

For more than 2,000 years,

Zeno’s mind-bending riddles have inspired

mathematicians and philosophers

to better understand the nature of infinity.

One of the best known of Zeno’s problems

is called the dichotomy paradox,

which means, “the paradox of cutting in two” in ancient Greek.

It goes something like this:

After a long day of sitting around, thinking,

Zeno decides to walk from his house to the park.

The fresh air clears his mind

and help him think better.

In order to get to the park,

he first has to get half way to the park.

This portion of his journey

takes some finite amount of time.

Once he gets to the halfway point,

he needs to walk half the remaining distance.

Again, this takes a finite amount of time.

Once he gets there, he still needs to walk

half the distance that’s left,

which takes another finite amount of time.

This happens again and again and again.

You can see that we can keep going like this forever,

dividing whatever distance is left

into smaller and smaller pieces,

each of which takes some finite time to traverse.

So, how long does it take Zeno to get to the park?

Well, to find out, you need to add the times

of each of the pieces of the journey.

The problem is, there are infinitely many of these finite-sized pieces.

So, shouldn’t the total time be infinity?

This argument, by the way, is completely general.

It says that traveling from any location to any other location

should take an infinite amount of time.

In other words, it says that all motion is impossible.

This conclusion is clearly absurd,

but where is the flaw in the logic?

To resolve the paradox,

it helps to turn the story into a math problem.

Let’s supposed that Zeno’s house is one mile from the park

and that Zeno walks at one mile per hour.

Common sense tells us that the time for the journey

should be one hour.

But, let’s look at things from Zeno’s point of view

and divide up the journey into pieces.

The first half of the journey takes half an hour,

the next part takes quarter of an hour,

the third part takes an eighth of an hour,

and so on.

Summing up all these times,

we get a series that looks like this.

“Now”, Zeno might say,

“since there are infinitely many of terms

on the right side of the equation,

and each individual term is finite,

the sum should equal infinity, right?”

This is the problem with Zeno’s argument.

As mathematicians have since realized,

it is possible to add up infinitely many finite-sized terms

and still get a finite answer.

“How?” you ask.

Well, let’s think of it this way.

Let’s start with a square that has area of one meter.

Now let’s chop the square in half,

and then chop the remaining half in half,

and so on.

While we’re doing this,

let’s keep track of the areas of the pieces.

The first slice makes two parts,

each with an area of one-half

The next slice divides one of those halves in half,

and so on.

But, no matter how many times we slice up the boxes,

the total area is still the sum of the areas of all the pieces.

Now you can see why we choose this particular way

of cutting up the square.

We’ve obtained the same infinite series

as we had for the time of Zeno’s journey.

As we construct more and more blue pieces,

to use the math jargon,

as we take the limit as n tends to infinity,

the entire square becomes covered with blue.

But the area of the square is just one unit,

and so the infinite sum must equal one.

Going back to Zeno’s journey,

we can now see how how the paradox is resolved.

Not only does the infinite series sum to a finite answer,

but that finite answer is the same one

that common sense tells us is true.

Zeno’s journey takes one hour.

译者:Andrea McDonough
审稿人:Bedirhan Cinar

这是 Elea 的 Zeno,

一位古希腊哲学家,

以发明许多悖论而闻名,这些

论点看似合乎逻辑,

但其结论却是荒谬或矛盾的。

2000 多年来,

芝诺令人费解的谜语启发了

数学家和

哲学家更好地理解无穷大的本质。

芝诺最著名的问题之一

被称为二分悖论

,在古希腊语中意为“一分为二的悖论”。

事情是这样的:

经过一整天的闲坐思考,

芝诺决定从他家步行到公园。

新鲜空气让他头脑清醒

,帮助他更好地思考。

为了去公园,

他首先必须走到公园的一半。

他的这部分旅程

需要一些有限的时间。

一旦他到达中途点,

他需要走剩下的一半距离。

同样,这需要有限的时间。

一旦他到达那里,他仍然需要走

剩下的一半距离,

这又需要有限的时间。

这种情况一次又一次地发生。

你可以看到我们可以一直这样下去,

把剩下的距离

分成越来越小的部分,

每个部分都需要一些有限的时间来遍历。

那么,芝诺到公园需要多长时间?

好吧,要找出答案,您需要添加

每个旅程的时间。

问题是,这些有限尺寸的碎片有无数个。

那么,总时间不应该是无穷大吗?

顺便说一句,这个论点是完全笼统的。

它说从任何地方旅行到任何其他地方

都应该花费无限的时间。

换句话说,它说所有运动都是不可能的。

这个结论显然是荒谬的,

但逻辑上的缺陷在哪里?

为了解决这个悖论,

把故事变成一个数学问题是有帮助的。

让我们假设芝诺的房子离公园一英里

,芝诺以每小时一英里的速度走路。

常识告诉我们,旅途的时间

应该是一小时。

但是,让我们从芝诺的角度来看事情

,并将旅程分成几部分。

旅程的前半段需要半个小时

,下半段需要一刻钟

,第三段需要八分之一小时,

以此类推。

总结所有这些时间,

我们得到一个看起来像这样的系列。

“现在”,芝诺可能会说,

“因为等式右边有无数个项

而且每个单独的项都是有限的

,总和应该等于无穷大,对吧?”

这就是芝诺论证的问题。

正如数学家后来意识到的那样

,可以将无限多个有限大小的项相加

,仍然得到一个有限的答案。

“如何?” 你问。

好吧,让我们这样想。

让我们从一个面积为一米的正方形开始。

现在让我们将正方形切成两半,

然后将剩下的一半切成两半,

依此类推。

在我们这样做的同时,

让我们跟踪碎片的区域。

第一个切片分为两部分,

每个部分的面积为

一半。下一个切片将其中一个分成两半,

依此类推。

但是,无论我们将盒子切片多少次

,总面积仍然是所有碎片的面积之和。

现在你可以明白为什么我们选择这种特殊

的切割正方形的方式了。

我们获得了与芝诺旅行时相同的无限系列。

随着我们构建越来越多的蓝色块

,用数学术语来说,

当我们将极限作为 n 趋于无穷大时

,整个正方形都被蓝色覆盖。

但是正方形的面积只是一个单位

,所以无限和必须等于一。

回到芝诺的旅程,

我们现在可以看到悖论是如何解决的。

不仅无限级数总和得到一个有限答案,

而且这个有限答案

与常识告诉我们的答案相同。

芝诺的旅程需要一个小时。